If one solution is 1000 x as acidic as another, how many pH units would there be between the two?
what is log 1000?
ANS: 10^3=1000
log 1000=3
The pH scale is logarithmic, meaning that each unit represents a tenfold difference in acidity. Therefore, if one solution is 1000 times as acidic as another, there would be 3 pH units between them.
To calculate this, you can use the following formula:
pH difference = log(base 10) (acidic solution / less acidic solution)
In this case, the calculation would be:
pH difference = log(base 10) (1000)
Using a calculator, you will find that log(base 10) (1000) is equal to 3.
To determine the number of pH units between two solutions that differ by a factor of 1000 in acidity, you can use the logarithmic nature of the pH scale. The pH scale is a logarithmic scale that measures the concentration of hydrogen ions (H+) in a solution.
The pH scale ranges from 0 to 14, where 0 represents highly acidic and 14 represents highly alkaline (basic) solutions. Each pH unit represents a tenfold difference in acidity or alkalinity.
Given that one solution is 1000 times as acidic as the other, we need to determine how many pH units are needed to represent this 1000-fold difference.
We can use the logarithmic equation:
pH = -log [H+]
Let's assume the less acidic solution has a pH value of x. Since it is 1000 times less acidic, the more acidic solution will have a pH value of x - log(1000).
Now, we can calculate the difference in pH units between the two solutions:
pH difference = (x - log(1000)) - x
Simplifying the equation:
pH difference = -log(1000)
Using logarithmic rules, log(1000) can be simplified as follows:
log(1000) = log(10^3) = 3
Therefore, the pH difference between the two solutions would be 3 pH units.