The molecular weight of CaCl2 is 110.98 g/mol. In order to make up 500.0 ml of a 0.500 M solution, you need how many g?
How many moles do you need? That is M x L = mols.
Then mol CaCl2 = grams CaCl2/molar mass CaCl2.
To find the number of grams needed to make up a specific volume of a solution with a given molarity, you can use the formula:
Mass (g) = Volume (L) * Molarity (mol/L) * Molecular Weight (g/mol)
Let's apply this formula to the given information:
Volume (L) = 500.0 mL = 500.0 mL * (1 L / 1000 mL) = 0.500 L
Molarity (mol/L) = 0.500 M
Molecular Weight (g/mol) = 110.98 g/mol
Now, substitute these values into the formula:
Mass (g) = 0.500 L * 0.500 mol/L * 110.98 g/mol
Calculate the result:
Mass (g) = 0.500 L * 0.500 mol/L * 110.98 g/mol
Mass (g) = 27.745 g
Therefore, you would need approximately 27.745 grams of CaCl2 to make up 500.0 mL of a 0.500 M solution.