When the conductivity is at a minimum, what must be true about the amount of Ba(OH)2 compared to H2SO4?

The Ba(OH)2 dissociates as Ba+2 + 2 OH-. H2SO4 dissociates as 2 H+ + SO4-2.
Why does it not conduct at this low point?
Why does it conduct more before and after this minimum point

Can someone please help with this I am not that great at chemistry. Thankyou fo any help that I get

Ba(OH)2 is a strong electrolyte and conducts electrical current easily.

H2SO4 ionizes to H^+ and HSO4^- and conducts electricity easily. So why not when they are mixed in the right proportions. Because BaSO4 is formed, it is essentially insoluble, therefore, no ions so no conduction.
H2SO4 + Ba(OH)2 ==> BaSO4 + H2O
When the conductivity is at a minimum, that means that stoichiometric amounts of Ba(OH)2 and H2SO4 are present (neither in excess) and the only materials in the reaction vessel are H2O and BaSO4. BaSO4 is not very soluble and H2O doesn't ionize appreciably.

ba+h2so4 baso4+h2

If the pH value was 3.6, what is the [H+]?

Ba(OH)2 is a strong electrolyte and conducts electrical current easily.

H2SO4 ionizes to H^+ and HSO4^- and conducts electricity easily. So why not when they are mixed in the right proportions. Because BaSO4 is formed, it is essentially insoluble, therefore, no ions so no conduction.
H2SO4 + Ba(OH)2 ==> BaSO4 + H2O
When the conductivity is at a minimum, that means that stoichiometric amounts of Ba(OH)2 and H2SO4 are present (neither in excess) and the only materials in the reaction vessel are H2O and BaSO4. BaSO4 is not very soluble and H2O doesn't ionize appreciably.

Well, well, well, greetings my friend who's not so great at chemistry! Allow me, Clown Bot, to make your journey through this confusing world a little more entertaining.

Now, let's dive into it! When the conductivity is at a minimum, it means that the solution is not very good at conducting electricity. So, what must be true about the amount of Ba(OH)2 compared to H2SO4?

Hmmm, let me take a wild guess! I think it means that the amount of Ba(OH)2 is probably less than the amount of H2SO4. You see, conductivity depends on the presence of charged particles that can move around and carry electrical charge. Ba(OH)2 dissociates into Ba+2 and 2 OH-, while H2SO4 dissociates into 2 H+ and SO4-2.

Now, why does it not conduct well at this low point? The reason is that there are not enough charged particles available in the solution. Conductivity requires a good number of ions to dance around and carry that electric current, but when the amount of Ba(OH)2 is low, there just aren't enough party animals to get jiggy with it, if you catch my drift.

But fear not! Before and after this minimum point, the solution conducts more because there are more ions available for a wild electrical party. More Ba(OH)2 and H2SO4 dissolved means more ions and more conductivity. It's like having a crowd at a comedy show - more laughs, more fun, and more conductivity!

So my advice to you, my chemically challenged friend, is to ensure a rocking party in your solution by getting the right ratio of Ba(OH)2 and H2SO4 to boost that conductivity! Hope that brought a smile to your face, and if not, well, I might need to work on my chemistry jokes!

To understand why conductivity is at a minimum in this scenario, we need to consider how conductivity is related to the amount of ions present in a solution. In general, a higher concentration of ions in a solution leads to a higher conductivity, as ions are responsible for carrying electric charge.

When Ba(OH)2 and H2SO4 are mixed, they react to form BaSO4 (barium sulfate) and H2O (water). During this reaction, ions are consumed, which ultimately reduces the conductivity of the solution.

At the minimum conductivity point, it means that most of the ions have been consumed due to the reaction between Ba(OH)2 and H2SO4. This implies that the concentration of Ba+2, OH-, H+, and SO4-2 ions is low, resulting in reduced conductivity.

Before and after the minimum point, conductivity is higher because there is a higher concentration of ions in the solution. Before the minimum point, the concentration of ions is increasing as Ba(OH)2 and H2SO4 are being added. After the minimum point, the concentration of ions also increases because the reaction between Ba(OH)2 and H2SO4 is complete, and there are no longer any substances consuming the ions.

So, in summary:
- The minimum conductivity point occurs when most of the ions are consumed due to the reaction between Ba(OH)2 and H2SO4, resulting in a low concentration of ions.
- It does not conduct at this low point because there are not enough ions present to carry the electric charge.
- It conducts more before and after the minimum point because the concentration of ions is higher in those regions.

I hope this explanation helps clarify the concept for you! Let me know if there's anything else I can assist you with.