MATH

X= 92]96]100]104]108
Y=23]24]25]26]27

WHAT IS THE VALUE OF Y WHEN X IS 68??

IF Y=X-19, WHAT IS THE VALUE OF X WHEN Y= 34

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  1. Question 1:

    92 - 4 = 88; y = 22
    88 - 4 = 84; y = 21
    84 - 4 = 80; y = 20
    80 - 4 = 76; y = 19
    76 - 4 = 72; y = 18
    72 - 4 = 68; y = 17

    What's the answer?

    When x = 68, y = 17.

    ====================

    For question 2:

    IF Y = X-19, WHAT IS THE VALUE OF X WHEN Y= 34.

    Replace Y with 34 and solve for x.

    34 = X - 19

    34 + 19 = X

    53 = X

    Done!

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  2. X= 92]96]100]104]108
    differences
    4, 4, 4, 4

    Y=23]24]25]26]27
    differences
    1, 1, 1, 1

    when doing this type of problem, make table of change in x and change in y.
    if the ratio of change in y over change in x is constant, we have a straight line.
    y = m x + b
    If not, make another line, the differences of differences.
    if that ratio is constant, you have a parabola.
    y = a x^2 + b x + c

    etc. That will usually work
    Anyway, here we have y = m x + b
    put in two points to solve for m and b and you have everything.
    we can see from our table that m = change in y / change in x = 1/4
    so
    y = (1/4) x + b
    put in a point (92,23)
    23 = (1/4)(92) + b
    b = 0 remarkable
    SO
    y = (1/4) x
    so if x = 68, then y = 68/4 = 17

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