IMAGINE- a building 6400km. high. On the ground floor, a person weighs 175lbs when he steps on a spring scale how much would the man weigh on the same scale if he were standing at the top floor? HINT: Note that 6400km is also the radius of the earth so that the top floor is 2Re from the earths center. Think about what this means for Fgrav before you start plugging in numbers or making conversions
I KNOW THIS MUCH----- confuesed what to plug in where. and what not to plug in. The weight is equal ‘mg”
On the Earth surface acceleration due to gravity is
mg=GmM/R²,
g=G•M•/R²,
where
the gravitational constant G =6.67•10^-11 N•m²/kg²,
Earth’s mass is M = 5.97•10^24 kg,
Earth’s radius is R = 6.378•10^6 m.
g=9.8 m/s²
Let's find “g” at the height “h” . Distance between the mas “m” (the person) and the center of the Earth is 2R =>
m•g1= G•m•M/(2R)²
g1= G•M/4R²=g/4
In the "high" building mg1= mg/4
•answered below - Damon, Monday, July 23, 2012 at 7:32pm
if r = 2R then r^2 = 4 R^2
then weight = (1/4) original
•PHYSICS! okay so would it be
(6.67*10^-11)(5.97*10^24)(77.87)/4(6.378*10^6)^2?!?!?!
175/4
Read the HINT !!!
okay sorry i don't understand physics. where did you get the 4 from? 2^2?!
To find the weight of the person on the top floor of the building, you can use the equation:
weight = (1/4) * original weight
But before plugging in numbers, let's break down the equation and understand what each variable represents.
- "weight" represents the weight of the person on the top floor.
- "original weight" represents the weight of the person on the ground floor.
Now let's substitute the values for the variables:
- original weight = 175 lbs (given)
- weight = (1/4) * original weight
Now, plug in the given value for the original weight:
- weight = (1/4) * 175 lbs
Simplifying the equation:
- weight = 0.25 * 175 lbs
- weight = 43.75 lbs
Therefore, the person would weigh 43.75 pounds on the same scale if they were standing on the top floor of the building.