Steve's boat will go 14 miles per hour in still water. If he can go 13 miles downstream in the same amount of time as it takes to go 10 miles upstream, then what is the speed of the current? (Please round your answer to one decimal place.)
didn't you even look at this one I answered for you?
It is the same type of question
http://www.jiskha.com/display.cgi?id=1343099701
To solve this problem, we can use the formula: speed = distance / time.
Let's assume the speed of the current is "c" miles per hour.
When Steve is going downstream, the effective speed of the boat is the sum of the boat's speed in still water and the speed of the current, so it is (14 + c) mph. We are told that Steve can go 13 miles downstream in the same amount of time it takes to go 10 miles upstream.
Therefore, the time taken downstream is equal to the time taken upstream.
The time taken to go downstream is distance / speed, so it is 13 / (14 + c).
The time taken to go upstream is distance / speed, so it is 10 / (14 - c).
Since the times are equal, we have the equation 13 / (14 + c) = 10 / (14 - c).
To solve for c, we can cross-multiply and solve the resulting equation.
(13)(14 - c) = (10)(14 + c)
182 - 13c = 140 + 10c
23c = 42
c = 42 / 23 ≈ 1.8
So, the speed of the current is approximately 1.8 miles per hour.