What is the oxidation state and covalency of [AlBr(Na3)5]+5
To determine the oxidation state and covalency of the given compound [AlBr(Na3)5]+5, we need to break down the compound and analyze each individual element separately.
Let's break down [AlBr(Na3)5]+5:
- [AlBr(Na3)5]+5 consists of an aluminum ion (Al^3+), surrounded by five sodium ions (Na^+) and one bromine ion (Br^-). The sodium ion has a +1 charge, the bromine ion has a -1 charge, and the overall charge of the compound is +5.
Now, let's analyze the oxidation state and covalency of each element:
- Aluminum (Al): Since the overall charge of the compound is +5 and there is only one aluminum ion, we can deduce that the oxidation state of aluminum is +3. Covalency refers to the number of chemical bonds formed by an atom. Aluminum is a metal and typically forms ionic bonds, so it does not have covalency.
- Bromine (Br): With a charge of -1, bromine has an oxidation state of -1. Bromine is a non-metal and typically forms covalent bonds. Therefore, it has a covalency of 1.
- Sodium (Na): Each sodium ion (Na^+) has a charge of +1. Sodium is also a metal and typically forms ionic bonds, so it does not have covalency.
In summary, the oxidation state of aluminum is +3, the oxidation state of bromine is -1, and neither aluminum nor sodium has covalency in this compound.