The red spinner has six equal sectors labeled with numbers 1 through 6. The blue spinner has four equal sectors labeled with letters A, B, C, and D. Find the probability of spinning the two spinners and getting a number less than three with a B or D.
Assume spinning of both spinners are random and independent of each other.
Red spinner is labeled 1 to 6, consequently the event of spinning less than three is 1 or 2 (two outcomes) out of 6 possible outcomes for a probability of 2/6=1/3.
Blue spinner has 4 sectors (4 possible outcomes). The event of spinning B or D means 2 outcomes out of the 4 possible, with a probability of 2/4=1/2.
Since the spinners are independent, the joint probability of getting both events happening is the product of the two individual probabilities.
To find the probability of spinning the red spinner and getting a number less than three, we need to determine the number of favorable outcomes and the total number of possible outcomes.
For the red spinner, there are two numbers less than three (1 and 2) out of six possible outcomes (numbers 1, 2, 3, 4, 5, and 6). Therefore, the probability of spinning a number less than three on the red spinner is 2/6 or 1/3.
For the blue spinner, there are two favorable outcomes (letters B and D) out of four possible outcomes (letters A, B, C, and D). Hence, the probability of spinning a B or D on the blue spinner is 2/4 or 1/2.
To find the probability of both events happening together (spinning a number less than three on the red spinner and a B or D on the blue spinner), we multiply the probabilities: (1/3) * (1/2) = 1/6.
Therefore, the probability of spinning the red spinner and getting a number less than three with a B or D on the blue spinner is 1/6.
To find the probability of spinning the two spinners and getting a number less than three with a B or D, we need to determine the number of favorable outcomes and the total number of possible outcomes.
Let's start by analyzing the red spinner. It has six equal sectors labeled with numbers 1 through 6. Since we are interested in getting a number less than three, the favorable outcomes are the numbers 1 and 2. Therefore, the red spinner has 2 favorable outcomes.
Next, let's consider the blue spinner. It has four equal sectors labeled with letters A, B, C, and D. We are interested in getting a B or D. Therefore, the favorable outcomes are the letters B and D. The blue spinner has 2 favorable outcomes.
Now, let's find the total number of possible outcomes. Since the red spinner has six equal sectors and the blue spinner has four equal sectors, the total number of possible outcomes is determined by multiplying the number of sectors on each spinner. Hence, the total number of possible outcomes is 6 * 4 = 24.
To find the probability, we divide the number of favorable outcomes by the total number of possible outcomes. Therefore, the probability is (2 favorable outcomes) / (24 total outcomes) = 1/12.
Therefore, the probability of spinning the two spinners and getting a number less than three with a B or D is 1/12.