An identification code is to consist of
two letters followed by six digits. How many different codes if repetition is permitted.
suppose that A=(58,3,4),B=(-2,18,24),and C=(-2,3,4) is triangle ABC a right triangle
To determine the number of different codes possible when repetition is permitted, we need to calculate the number of choices for each part of the code.
1. Two letters: Assuming the letters can be repeated, there are 26 choices for each letter (26 letters in the English alphabet). Since repetitions are allowed, the number of possible combinations is obtained by multiplying the number of choices together: 26 * 26 = 676.
2. Six digits: Assuming digits can be repeated, there are 10 choices for each digit (0-9). We have six digits, so the number of possible combinations is obtained by multiplying the number of choices: 10 * 10 * 10 * 10 * 10 * 10 = 1,000,000.
To find the total number of different codes, we multiply the number of possibilities for each part of the code together: 676 * 1,000,000 = 676,000,000.
Therefore, there are 676,000,000 different codes possible when repetition is permitted.