a man pushes a box of mass 5 kg in a horizontal direction by 10 N force on the surface through a distance of 5m if the cofficien of kinetic friction is 0.2 the total work done on the box is
Work done by the man = F*d = 10*5 = 50 J
work done by frictional force = mu*mg*d
= - 0.2*5*9.8*5 = - 49 J
Net work done on the box = 50-49= 1 J