Math

Find the exact solution to 6x^2+1=-8x by using the Quadratic Formula.

A)-4+-(sqrt10)
B)-4+-(sqrt22)/6
C)-2+-2(sqrt10)/3
D)-4+-(sqrt10)/6
I chose C

x=-b+-(sqrtb^2-4ac)/2a
x=--8+-(sqrt-8^2-4(6)(1))/2(6)
x=8+-(sqrt64-24)/12
x=8+-(sqrt40)/12
x= C

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  1. correct

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  2. In the first one a = 6, b = 8 and c = 1
    x = [-8 +-sqrt (64-24)]/12
    =[-8 +-sqrt(4*10)]/12
    =[-8 +-2sqrt(10)]/12
    =[-4 +-sqrt10]/6
    So your amswer is wrong.

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  3. Thanks for picking up on that
    As George would have said,
    "I guess I mislooked"

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  4. Please explain x = [-8 +-sqrt (64-24)]/12
    =[-8 +-sqrt(4*10)]/12

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  5. 64 - 24 = 40 = 4*10

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  6. I did all the steps

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  7. i don't understand

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  8. a = 6
    b = 8
    c = 1
    why did you use -8 for b?
    why dis you not divide -b by 2a?
    you left a bracket out, wrecking everything
    x = [ -8 +/- sqrt (64 - 4*6*1) ] /2*6
    x = [ -8 +/- sqrt(64-24) ] / 12
    x = [ -8 +/- sqrt (4*10) ] /12
    x = [ -8 +/- 2 sqrt (10) ] / 12
    x = [ -4 +/- sqrt(10) ] / 6
    I agree with drwls :)

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  9. Which don't you understand:
    64-24 = 40, or
    40 = 4 x 10?
    Or my use of * for x when multiplying?
    We do that often here to avoid confusion with the algebraic variable x.

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