the volume of a gas at 273 degree cels and 2 atm pressure is 5L. What would be its volume at 0 degree celsius and 1 atm pressure ?
(P1V1/T1) = (P2V2/T2)
Remember T must be in kelvin.
To find the volume of the gas at 0 degrees Celsius and 1 atm pressure, we can use the combined gas law. The combined gas law states that the ratio of the initial volume (V1) to the final volume (V2) is equal to the ratio of the initial temperature (T1) to the final temperature (T2) multiplied by the ratio of the final pressure (P2) to the initial pressure (P1).
The formula for the combined gas law is:
(V1 / T1) * (P1 / P2) = (V2 / T2)
Let's plug in the values you provided:
V1 = 5 L
T1 = 273 degrees Celsius (convert to Kelvin: 273 + 273 = 546 K)
P1 = 2 atm
T2 = 0 degrees Celsius (convert to Kelvin: 0 + 273 = 273 K)
P2 = 1 atm
Now we can find V2:
(5 L / 546 K) * (2 atm / 1 atm) = (V2 / 273 K)
(5 L / 546 K) * 2 = V2 / 273 K
(5 L / 546 K) * 2 * 273 K = V2
V2 = (5 L / 546 K) * 2 * 273 K
V2 = (5 * 2 * 273) / 546
V2 = 10 * 273 / 546
V2 = 5 L
Therefore, the volume of the gas at 0 degrees Celsius and 1 atm pressure is also 5 liters.