How much work is done by a person lifting 2 Kg object from a bottom of a well at constant speed of 2 m is
W=mgh=2•9.8•2=39.25 J
To determine the amount of work done by a person lifting a 2 kg object from the bottom of a well at a constant speed of 2 m, we need to use the formula for work.
Work (W) is defined as the product of force (F) and the displacement (d) in the direction of the force. Mathematically, it can be expressed as:
W = F * d * cos(theta)
Where theta is the angle between the applied force and the direction of displacement. In this case, the person is lifting the object vertically, so the angle between the force and displacement is 0 degrees, and cos(0) = 1. Therefore, we can simplify the equation to:
W = F * d
The force required to lift the object is equal to the weight of the object, which can be calculated using the formula:
Force = mass * acceleration due to gravity
In this case, the mass is 2 kg, and the acceleration due to gravity is approximately 9.8 m/s^2. Thus, the force is:
Force = 2 kg * 9.8 m/s^2 = 19.6 N
The displacement is given as 2 m. Therefore, plugging the values into the equation, we get:
W = 19.6 N * 2 m = 39.2 Joules
So, the amount of work done by the person to lift the 2 kg object from the bottom of the well at a constant speed of 2 m is 39.2 Joules.