Initially a gas is at a pressure of 12 atm, a volume of 23 L, and a temperature of 200 K, and then the pressure is raised to 14 atm and the temperature to 300 K. What is the new volume of the gas? Round to the nearest tenth. Don't forget the units.

(P1V1/T1) = (P2V2/T2)

To solve this problem, we can use the combined gas law, which states:

(P1 * V1) / (T1) = (P2 * V2) / (T2)

where P1, V1, and T1 are the initial pressure, volume, and temperature, and P2, V2, and T2 are the final pressure, volume, and temperature.

Given:
Initial pressure (P1) = 12 atm
Initial volume (V1) = 23 L
Initial temperature (T1) = 200 K
Final pressure (P2) = 14 atm
Final temperature (T2) = 300 K

We need to find the final volume (V2).

Now, let's substitute the given values into the combined gas law equation:

(12 atm * 23 L) / (200 K) = (14 atm * V2) / (300 K)

To solve for V2, we can rearrange the equation:

V2 = ((12 atm * 23 L * 300 K) / (14 atm * 200 K)

Now, let's calculate the final volume (V2):

V2 = (82800 atm * L * K) / (2800 atm * K)
V2 = 29.57 L (rounded to the nearest tenth)

Therefore, the new volume of the gas is approximately 29.6 L.