A 0.3 kg ball strikes a wall head on and then rebounds straight back. The initial speed was 10.0 m/s and the speed after it rebounds was 1.9 m/s. What was the magnitude of the total impulse on the ball during the collision in N*s?
impulse= mass(changeinvelocity)
impulse=mass(1.9-(-10))=mass(11.9)
To find the magnitude of the total impulse on the ball during the collision, we can use the impulse-momentum principle. The impulse is equal to the change in momentum, and momentum is calculated by multiplying mass with velocity.
The formula for impulse is:
Impulse = Change in momentum = Final momentum - Initial momentum
Given:
Mass of the ball (m) = 0.3 kg
Initial velocity (u) = 10.0 m/s
Final velocity (v) = -1.9 m/s (negative sign indicates that the direction is opposite)
Step 1: Calculate the initial momentum (p_initial) of the ball.
Momentum (p_initial) = Mass (m) * Initial velocity (u)
p_initial = m * u
p_initial = 0.3 kg * 10.0 m/s
p_initial = 3.0 kg * m/s
Step 2: Calculate the final momentum (p_final) of the ball.
Momentum (p_final) = Mass (m) * Final velocity (v)
p_final = m * v
p_final = 0.3 kg * (-1.9 m/s) (negative sign indicates that the direction is opposite)
p_final = -0.57 kg * m/s
Step 3: Calculate the change in momentum (Δp).
Change in momentum (Δp) = Final momentum (p_final) - Initial momentum (p_initial)
Δp = p_final - p_initial
Δp = -0.57 kg * m/s - 3.0 kg * m/s
Δp = -3.57 kg * m/s
The magnitude of the total impulse on the ball during the collision is the absolute value of the change in momentum.
Magnitude of impulse = |Δp|
Magnitude of impulse = |-3.57 kg * m/s|
Magnitude of impulse = 3.57 kg * m/s
Therefore, the magnitude of the total impulse on the ball during the collision is 3.57 N*s.