SOLVE= log[6](x+3)+log[6](x+2)<2
A)-6<x<7
B)-6<x<2
C)3<x<7
D)-2<x<3
PLEASE HELP!!
log[6](x+3)+log[6](x+2)<2
log[6]((x+3)(x+2))<2
(x+3)(x+2) < 36
x^2 + 5x + 6 < 36
x^2 + 5x - 30 < 0
1/2 (-5-√145) < x < 1/2 (-5+√145)
Hmm. There appears to be a typo. However,
(x-3)(x+2) < 36
x^2 - x - 6 < 36
x^2 - x - 42 = 0
(x-7)(x+6) < 0
-6 < x < 7