In the balanced equation for the combustion of 2,2,4-trimethyloctane (C11H24), the coefficient of the organic compound is...the coefficient of oxygen gas is ...the coefficient of carbon dioxide gas is...and the coefficient of liquid water is.
This type is balanced by trial and error and it is a relatively simple one. What do you not understand about balancing by trial and error?
Drbob,
It is apparent that you understand Chemistry. I on the other hand do not. I here looking for direction, not to play silly mind games with you.
And I am here to help. I don't play silly mind games. I can balance all of the equations you post and it won't do you one bit of good. On the other hand, if I can identify some of the problems you have about understanding how to do these, perhaps I can show you how to do them. When you know how to do them you won't rely on others to do them for you.
To determine the coefficients of the balanced equation for the combustion of 2,2,4-trimethyloctane (C11H24), we need to follow a step-by-step process. Here's how to do it:
1. Start by writing the unbalanced equation for the combustion reaction:
C11H24 + O2 → CO2 + H2O
2. Count the number of atoms on both sides of the equation.
- On the left side:
- Carbon (C): 11 (from C11H24)
- Hydrogen (H): 24 (from C11H24)
- Oxygen (O): 2 (from O2)
- On the right side:
- Carbon (C): 1 (from CO2)
- Hydrogen (H): 2 (from H2O)
- Oxygen (O): 3 (from CO2 and H2O)
3. To balance the carbon (C) atoms:
Since there are 11 carbon atoms on the left side and only 1 on the right side, we need to put a coefficient of 11 in front of CO2:
C11H24 + O2 → 11CO2 + H2O
4. To balance the hydrogen (H) atoms:
Since there are 24 hydrogen atoms on the left side and only 2 on the right side, we need to put a coefficient of 12 in front of H2O to achieve the desired number of 24 hydrogens:
C11H24 + O2 → 11CO2 + 12H2O
5. To balance the oxygen (O) atoms:
To count the number of oxygen atoms on the left side, we have 2 from O2 and 44 (11 × 4) from 11 CO2. Altogether, there are 46 oxygen atoms.
Since there are already 2 oxygen atoms from O2 on the left side, we need to add 44 more oxygen atoms on the right side. This can be achieved by adding a coefficient of 22 in front of O2.
C11H24 + 22O2 → 11CO2 + 12H2O
Therefore, the coefficients for the balanced equation are:
- The coefficient of 2,2,4-trimethyloctane (C11H24) is 1.
- The coefficient of oxygen gas (O2) is 22.
- The coefficient of carbon dioxide gas (CO2) is 11.
- The coefficient of liquid water (H2O) is 12.