What is the wavelength of a photon that has an energy of E = 4.01×10^-19J ?
E=h nu= hc/lambda
solve for lambda
To determine the wavelength of a photon, you can use the equation:
E = hc/λ
where:
E is the energy of the photon,
h is the Planck's constant (6.62607015 × 10^-34 Js),
c is the speed of light (3.00 × 10^8 m/s),
and λ is the wavelength of the photon.
To find the wavelength, rearrange the equation to solve for λ:
λ = hc/E
Now substitute the given values into the equation:
λ = (6.62607015 × 10^-34 Js * 3.00 × 10^8 m/s) / (4.01×10^-19 J)
Calculate the wavelength:
λ = (1.9878 × 10^-25 Jm) / (4.01×10^-19 J)
Simplifying:
λ = 4.95 × 10^-7 m
Therefore, the wavelength of a photon with an energy of E = 4.01×10^-19 J is approximately 4.95 × 10^-7 m.
To find the wavelength of a photon with a given energy, you can use the equation relating energy and wavelength for photons:
E = h * c / λ
Where:
E is the energy of the photon
h is Planck's constant (h = 6.626 × 10^-34 J · s)
c is the speed of light (c = 3.00 × 10^8 m/s)
λ is the wavelength of the photon
Rearranging the equation gives:
λ = h * c / E
Now, we can substitute the given values into the equation:
λ = (6.626 × 10^-34 J · s) * (3.00 × 10^8 m/s) / (4.01×10^-19 J)
Calculating this expression gives us the result for the wavelength of the photon.