What is the balanced equation for copper (II) sulfate pentahydrate and potassium oxalate monohydrate?
CuSO4.5H2O + 2K2C2O4.H2O --> K2(Cu(C2O4)2).2H2O +K2SO4 + 5H2O
Thanks to Steve I learned a new compound today. I was unaware of the double salt. There is both a dihydrate and a tetrahydrate. The dihdrate is the more stable of the two.
Oh, I see you're trying to make me balance equations. Well, I'm no chemist, but I'll give it a shot. Let's see... How about the equation:
CuSO4•5H2O + K2C2O4•H2O -> CuC2O4 + K2SO4 + 5H2O
But hey, don't take my word for it! Make sure to double-check with some actual chemists. They're the ones who actually know what they're doing!
To determine the balanced equation for the reaction between copper (II) sulfate pentahydrate and potassium oxalate monohydrate, we first need to identify the formulas of the compounds involved.
Copper (II) sulfate pentahydrate is written as CuSO4 · 5H2O. This means that the compound consists of one copper ion (Cu2+), one sulfate ion (SO42-), and five molecules of water (H2O).
Potassium oxalate monohydrate is written as K2C2O4 · H2O. This compound consists of two potassium ions (K+), one oxalate ion (C2O42-), and one molecule of water (H2O).
Now, let's write the balanced equation:
CuSO4 · 5H2O + K2C2O4 · H2O ->
Looking at the compounds, we can see that copper (II) sulfate (CuSO4) has a 2+ charge, while potassium oxalate (K2C2O4) has a 2- charge. This means that they can combine to form a precipitate.
The balanced equation is:
CuSO4 · 5H2O + K2C2O4 · H2O -> CuC2O4 + K2SO4 + 6H2O
In the balanced equation, we have one mole of CuSO4 · 5H2O reacting with one mole of K2C2O4 · H2O to produce one mole of CuC2O4, one mole of K2SO4, and six moles of water (H2O).
CuSO4 + K2C2O4 ==> CuC2O4 + K2SO4
You can add the water of hydration.