a racing car has a uniform acceleration of 4ms-2. what distances will it cover in 10s after start?
as
a=v/s
and
v=d/s
d=??
so
a=d/s^2
by putting v in a eq
then
d=a*s^2
plug vlaues
d = (1/2) a t^2
where a = 4 m/s^2 and t =10 s
d = (1/2)(4)(100)
d = 200 meters
To calculate the distance covered by a racing car with uniform acceleration, you can use the following formula:
d = ut + (1/2)at^2
Where:
d = Distance covered
u = Initial velocity (assuming the car starts from rest, u = 0)
a = Acceleration
t = Time
Given that the acceleration of the racing car is 4 m/s^2 and the time is 10 seconds, we can substitute these values into the formula:
d = 0(10) + (1/2)(4)(10)^2
d = 0 + (1/2)(4)(100)
d = 0 + 2(100)
d = 0 + 200
Therefore, the racing car will cover a distance of 200 meters after 10 seconds of starting.