The solubility of NaCl in water at 100 degrees celsius is 39.1 g/100 g water. Calculate the boiling point of this solution?
To calculate the boiling point of a solution, we need to know the boiling point elevation constant (Kb) and the molality (m) of the solute. The boiling point elevation constant is a property of the solvent, which in this case is water.
However, the information given in the question does not provide the necessary data for calculating the boiling point elevation. We need either the molality of the solute or the boiling point elevation constant.
If you have the molality of NaCl in the solution or the boiling point elevation constant, please provide that information, and I can help you calculate the boiling point of the solution.
To calculate the boiling point elevation, we can use the equation:
ΔTb = Kb * m
Where:
ΔTb = boiling point elevation
Kb = molal boiling point elevation constant (for water, it is approximately 0.512 ºC/m)
m = molality of the solution (moles of solute/kg of solvent)
First, we need to find the molality of the solution:
1. Calculate the moles of NaCl:
moles of NaCl = mass of NaCl / molar mass of NaCl
= 39.1 g / (22.99 g/mol + 35.45 g/mol)
= 39.1 g / 58.44 g/mol
≈ 0.669 mol NaCl
2. Calculate the mass of water used to dissolve the NaCl:
mass of water = 100 g - 39.1 g
= 60.9 g
3. Calculate the molality using the moles of NaCl and mass of water:
molality = moles of NaCl / mass of water (kg)
= 0.669 mol / 0.0609 kg
≈ 10.97 mol/kg
Now, we can calculate the boiling point elevation:
ΔTb = Kb * m
= 0.512 ºC/m * 10.97 mol/kg
≈ 5.62 ºC
Finally, we can calculate the boiling point of the solution:
Boiling point of water = 100 ºC (normal boiling point of water at sea level)
Boiling point of solution = Boiling point of water + ΔTb
= 100 ºC + 5.62 ºC
≈ 105.62 ºC
Therefore, the boiling point of the solution is approximately 105.62 ºC.