How to fully factor X^3-8.
pls help
The difference of cubes formula is:
x^3 − y^3 = (x − y)*(x^2 + xy + y^2)
Your x is x in this case and y = 8 (2^3).
So you get:
x^3 - 2^3 = (x - 2)*(x^2 + 2x + 4).
pls help
x^3 − y^3 = (x − y)*(x^2 + xy + y^2)
Your x is x in this case and y = 8 (2^3).
So you get:
x^3 - 2^3 = (x - 2)*(x^2 + 2x + 4).