Calculate the pH of 1.7M of KCl
Neither K^+ nor Cl^- are hydrolyzed; therefore, the pH is just that of H2O.
(H^+)(OH^-) = Kw = 1E-14.
Solve for H^+ and convert to pH. pH = 7.00.
Note: I assume this is a lower level course; if not that you must calculate the ionic strength of the 1.7M KCl solution and the pH will not be 7.00