5. Eliminate the parameter and write the corresponding rectangular equations: x=3-2sin theta and y=1+5 cos theta
x = 3-2sinθ
y = 1+5cosθ
since sin^2θ+cos^2θ = 1,
[(x-3)/2]^2 + [(y-1)/5]^2 = 1
(x-3)^2/4 + (y-1)^2/25 = 1
y = 1+5cosθ
since sin^2θ+cos^2θ = 1,
[(x-3)/2]^2 + [(y-1)/5]^2 = 1
(x-3)^2/4 + (y-1)^2/25 = 1