: a loaded truck with uniform acceleration covers the distance between two points 60m apart in 6 sec.its velocity as it passes the first point is 5 m/s .find the velocity at second point
What do you know?
Initial velocity 5 m/s
Time 6s
Displacement (distance, not quite the same)60m
Look at the standard motion equations, see if you can find one that uses all of these to give acceleration.
Then use v=u+at.
thanx charlie i got my answer
-chan
To find the velocity at the second point, we first need to determine the acceleration of the truck.
We can use the equation of motion:
v = u + at,
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
Given that the truck's initial velocity (at the first point) is 5 m/s, and the time taken to cover the distance between the two points is 6 seconds, we can substitute these values into the equation:
v = 5 + a * 6.
Now, we need to find the acceleration. Since the truck is traveling with uniform acceleration, we can use the equation:
s = ut + (1/2)at^2,
where s is the distance, u is the initial velocity, a is the acceleration, and t is the time.
Given that the truck covers a distance of 60 meters between the two points and the time taken is 6 seconds, we can substitute these values into the equation:
60 = 5 * 6 + (1/2) * a * 6^2.
Simplifying this equation, we get:
60 = 30 + 18a.
Rearranging the equation, we have:
18a = 60 - 30,
18a = 30,
a = 30 / 18,
a = 5/3 m/s^2.
Now that we have the acceleration, we can substitute it back into the initial equation to find the final velocity at the second point:
v = 5 + (5/3) * 6,
v = 5 + 10,
v = 15 m/s.
Therefore, the velocity of the loaded truck at the second point is 15 m/s.