An electric field of 264,000 N/C points due west at a certain spot. What are the magnitude and direction of the force that acts on a charge of -6.3 µC at this spot?

1663200N

To find the force acting on a charge in an electric field, you can use the formula:

Force (F) = Electric field (E) x Charge (q)

Given:
Electric field (E) = 264,000 N/C (pointing due west)
Charge (q) = -6.3 µC = -6.3 x 10^-6 C

To find the magnitude of the force, substitute the given values into the formula:

F = E x q
F = (264,000 N/C) x (-6.3 x 10^-6 C)

To multiply the values together:
F = -1.6632 N

Therefore, the magnitude of the force acting on the charge is 1.6632 Newtons.

The negative sign indicates that the force is in the opposite direction to the electric field.

To determine the direction of the force, we know that the electric field is pointing due west. Since the charge is negative, it will experience a force in the opposite direction of the electric field.

Therefore, the direction of the force is due east.