which has the greater average speed: a car that travels from milepost 35 to milepost 40 in 5 minutes, or one that travels from milepost 68 to milepost 78 in 10 minutes?
V1 =40-35/5=1 m/min.
V2=78-68/10=10/10=1 m/min.
V1=V2
To determine which car has the greater average speed, we need to calculate the average speed of each car using the provided information. Average speed is calculated by dividing the total distance traveled by the time taken.
For the first car that travels from milepost 35 to milepost 40 in 5 minutes, we subtract the initial milepost from the final milepost to find the total distance traveled: 40 - 35 = 5 miles.
The time taken for this car is given as 5 minutes.
So, the average speed of the first car is: Distance / Time = 5 miles / 5 minutes = 1 mile per minute.
Now, let's calculate the average speed for the second car that travels from milepost 68 to milepost 78 in 10 minutes. The total distance traveled is: 78 - 68 = 10 miles.
The time taken for this car is given as 10 minutes.
So, the average speed of the second car is: Distance / Time = 10 miles / 10 minutes = 1 mile per minute.
Both cars have the same average speed of 1 mile per minute.