I need to derive a net ionic equation after balancing:
NA2PO4 (2-) +HI =?
what I have so far is
NA2Po4 +2HI = 2NAI +H3PO4
I can't get any farther but the answer is
HPO4 (2-) +H =H2PO4
can someone help me with the steps?
Na2HPO4 + HI ==> NaI + NaH2PO4.
This is a double displacement (double replacement) reaction.
One Na on Na2HPO4 changes places with the H of HI. That's all that happens. So Na2HPO4 becomes NaH2PO4 and the HI becomes NaI.
Check the problem and be careful with the caps. Na2PO4^2- doesn't exist. It could be Na2PO4^-. It might be Na2HPO4 and the equation would be
Na2HPO4 + HI ==> NaI + NaH2PO4 for which the net ionic equation is
HPO4^- + H^+ ==> H2PO4^-
you are right. It is Na2HPO4 + HI ==> NaI + NaH2PO4 for which the net ionic equation is
HPO4^- + H^+ ==> H2PO4^-
Can you explain how to get this, though? any steps would be helpful.
I think I've got it by looking through the balanced equation. It is just hard to understand the NA repeated twice on the right side of the equation.
To derive the net ionic equation after balancing the given equation:
Step 1: Write the balanced molecular equation.
The given equation is:
Na2PO4 (2-) + HI → [unbalanced equation]
To balance the equation, you need to ensure that the number of atoms on each side is equal.
Na2PO4 (2-) + 2HI → 2NaI + H3PO4
Step 2: Split the soluble compounds into ions.
Na2PO4 can be broken down into its constituent ions as follows:
2Na+ + PO4 (3-)
HI can be broken down into its constituent ions:
H+ + I-
Step 3: Identify the spectator ions.
The spectator ions are ions that appear on both sides of the equation without undergoing any chemical change. In this case, Na+ and I- are spectator ions as they appear on both sides of the equation.
Step 4: Form the net ionic equation.
Remove the spectator ions from the equation.
Remaining equation:
PO4 (3-) + H+ → H3PO4
Step 5: Simplify the net ionic equation.
H3PO4 is a weak acid, which means it does not fully ionize in solution. Therefore, we write it as HPO4 (2-) + H+.
Final net ionic equation:
HPO4 (2-) + H+ → H2PO4
In summary, after balancing the molecular equation and removing the spectator ions, the net ionic equation for the given reaction is:
HPO4 (2-) + H+ → H2PO4