can you please break this equation down for me.I saw how you got 0,0 but im confusing my self on the rest of the problems such as 3x+2y=-8

2x-3y=-1
heres my answer (-2,-1) am i correct?

To find out if you are right or not, put your answer (x =-2, y=-1) back in each equation

equation 1
3(-2) + 2(-1) = ??? -8
-6 - 2 = -8 sure enough

equation 2
2(-2) - 3(-1) = ??? -1
-4 + 3 = -1 sure enough so you did it right

Now the how :

equation 1
when x = 0, y = -8/2 so y intercept at (0,-4)
when y = 0, x = -8/3 so x intercept at (-8/3,0)
draw that line
equation 2
when x = 0, y = 1/3 so (0,1/3)
when y = 0, x = -1/2 so (-1/2, 0)
graph
see if they hit each other at (-2,-1)

To solve the system of equations:

1. 3x + 2y = -8
2. 2x - 3y = -1

You can use the method of substitution or the method of elimination. Let's use the method of substitution.

1. Solve equation 1 for x:
3x = -2y - 8
x = (-2y - 8) / 3

2. Substitute x in equation 2 with the value we just found:
2((-2y - 8) / 3) - 3y = -1

Let's simplify this equation:

(2(-2y - 8) / 3) - 3y = -1
(-4y - 16) / 3 - 3y = -1
(-4y - 16) - 9y = -3
-4y - 16 - 9y = -3
-13y - 16 = -3
-13y = 13
y = 13 / -13
y = -1

Now, substitute the value of y back into equation 1:

3x + 2(-1) = -8
3x - 2 = -8
3x = -8 + 2
3x = -6
x = -6 / 3
x = -2

Therefore, the solution to the system of equations is (x, y) = (-2, -1).

From your answer, (-2, -1), it looks like you are correct! Well done!