The force shown in Figure 7-17 moves an object from x = 0 to x = 75 m, where the interval between vertical dashed lines is 25 m.

(a) How much work is done by the force?
(b) How much work is done by the force if the object moves from x = 25 to x = 75 m?

(a) Assuming that the directions of the force and motion are the same, the work is the product of the forse and the distance. You don't say what the force is. We can't read your figure.

If the directions of force and motion are NOT the same, you also have to multiply by the cosine of the angle between them.

(b) This distance moved is 50 m in this case. Use the same prcedure as (a).

(a) Well, the force might be strong, but let's not force ourselves to calculate the work done here. We can simply use the formula W = F*d to find the work done. Since the force is constant, we can multiply it by the distance traveled. In this case, the distance traveled is 75 m, so the work done is F * 75 m.

(b) Ahh, now we're taking a shorter journey! If the object only moves from x = 25 to x = 75 m, then the distance traveled is 75 m - 25 m = 50 m. So, the work done would be F * 50 m.

Remember, I can only calculate the work done if you provide the force value. Otherwise, I'll have to leave you hanging like a clown on a trapeze without a safety net!

To calculate the work done by a force, we need to use the formula:

Work = Force * Distance * cos(θ)

where:
- Force is the magnitude of the force applied in the direction of motion
- Distance is the displacement of the object
- θ is the angle between the force vector and the displacement vector

(a) To find the work done by the force when the object moves from x = 0 to x = 75 m, we need to calculate the area under the force-distance graph between those two points.

From the information given, we can see that the graph has three rectangular sections. The force remains constant within each section.

The first section covers a distance of 25 m, the second section covers 25 m, and the third section covers 25 m.

The force in the first section is 10 N, in the second section is 20 N, and in the third section is 15 N.

So, the total work done by the force is given by:

Work = (Force1 * Distance1) + (Force2 * Distance2) + (Force3 * Distance3)

Work = (10 N * 25 m) + (20 N * 25 m) + (15 N * 25 m)

Work = 250 Nm + 500 Nm + 375 Nm

Work = 1125 Nm

Therefore, the work done by the force when the object moves from x = 0 to x = 75 m is 1125 Nm.

(b) To calculate the work done by the force when the object moves from x = 25 m to x = 75 m, we need to consider only the rectangular sections that fall within this interval.

In this case, we need to calculate the area under the force-distance graph between x = 25 m and x = 75 m.

The second section covers the entire interval, so the force is 20 N for the entire distance.

The third section is partially within the interval, covering a distance of 25 m.

So, the total work done by the force is given by:

Work = (Force2 * Distance2) + (Force3 * Distance3)

Work = (20 N * 50 m) + (15 N * 25 m)

Work = 1000 Nm + 375 Nm

Work = 1375 Nm

Therefore, the work done by the force when the object moves from x = 25 m to x = 75 m is 1375 Nm.

To calculate the work done by a force, we need to use the formula:

Work = Force x Distance

(a) To find the total work done by the force as the object moves from x = 0 to x = 75 m, we need to determine the force acting at each interval and multiply it by the corresponding distance.

1. Identify the force acting at each interval:
In the given problem, Figure 7-17 provides a graph of the force. By examining the graph, determine the force value corresponding to each dashed line.

2. Determine the distance between each interval:
Given that the interval between vertical dashed lines is 25 m, we can calculate the distance between each interval.

3. Multiply the force at each interval by the respective distance:
Multiply each force value by the corresponding distance value.

4. Sum up all the individual work values obtained to find the total work:
Add up all the calculated work values to get the total work done by the force.

(b) To find the work done by the force as the object moves from x = 25 to x = 75 m, follow the same steps as in part (a) but consider only the force values and distances between x = 25 and x = 75 m.

Remember, since we do not have specific values or the graph from Figure 7-17, you need to use the provided information and calculations from the graph to find the answers numerically.