to prepare 500cm^3 of glucose solution of concerntration 1M. The chemical formula of glucose is C6H12O6.calculate (1)the relative molecular mass and molar mass.(2)the amount of glucose which will be in the solution.(3)the mass of glucose to be weighed
To solve this problem, we need to follow these steps:
(1) Calculate the relative molecular mass and molar mass of glucose.
(2) Use the molar mass to determine the amount of glucose in the solution.
(3) Calculate the mass of glucose to be weighed.
Let's solve each step one by one:
(1) Relative Molecular Mass and Molar Mass of Glucose:
The chemical formula of glucose is C6H12O6.
To calculate the relative molecular mass, we sum up the atomic masses of each element in the formula:
Relative Molecular Mass of glucose = (6 * Atomic Mass of Carbon) + (12 * Atomic Mass of Hydrogen) + (6 * Atomic Mass of Oxygen)
Using the atomic masses from the periodic table:
Relative Molecular Mass of glucose = (6 * 12.01) + (12 * 1.01) + (6 * 16.00)
Relative Molecular Mass of glucose = 72.06 + 12.12 + 96.00
Relative Molecular Mass of glucose = 180.18 g/mol
Therefore, the relative molecular mass of glucose is 180.18 g/mol.
The molar mass is another term for the relative molecular mass. So, the molar mass of glucose is also 180.18 g/mol.
(2) Amount of Glucose in the Solution:
The concentration of the glucose solution is given as 1M, which means 1 mole of glucose dissolved in 1 liter of solution.
However, we need to prepare 500 cm^3 (or 500 ml) of the solution instead of 1 liter. To convert the volume to liters, divide 500 by 1000:
Volume of solution (in liters) = 500 cm^3 / 1000 cm^3/L
Volume of solution (in liters) = 0.5 L
Since the concentration is 1M, this means that 1 mole of glucose will be present in 1 liter of solution. Therefore, the amount of glucose in the solution will also be 1 mole.
(3) Mass of Glucose to be Weighed:
To calculate the mass of glucose to be weighed, we can use the formula:
Mass of Glucose = Amount of Glucose * Molar Mass
Substituting the values we found earlier:
Mass of Glucose = 1 mole * 180.18 g/mol
Mass of Glucose = 180.18 g
Therefore, to prepare 500 cm^3 of a 1M glucose solution, you would need to weigh 180.18 grams of glucose.