A 0.22-caliber handgun fires a 27-{\rm g} bullet at a velocity of 765 {\rm m}/{\rm s}.
Part A
Calculate the de Broglie wavelength of the bullet.
wavelength = h/mv
To calculate the de Broglie wavelength of the bullet, you can use the de Broglie equation:
λ = h / p
where λ is the wavelength, h is the Planck's constant (6.626 × 10^-34 m^2 kg/s), and p is the momentum of the bullet.
To find the momentum of the bullet, you can use the equation:
p = m * v
where p is the momentum, m is the mass of the bullet, and v is the velocity of the bullet.
Given that the mass of the bullet is 27 g (or 0.027 kg) and the velocity is 765 m/s, you can substitute these values into the equation to find the momentum:
p = (0.027 kg) * (765 m/s)
p ≈ 20.755 kg m/s
Now that you have the momentum, you can substitute it into the de Broglie equation to calculate the wavelength:
λ = (6.626 × 10^-34 m^2 kg/s) / (20.755 kg m/s)
λ ≈ 3.187 × 10^-36 m
Therefore, the de Broglie wavelength of the bullet is approximately 3.187 × 10^-36 meters.