a certain amount of water freezes and the resulting weight of the ice is
It is the same as the original amount of water.
To determine the resulting weight of the ice when a certain amount of water freezes, you need to know the density of water and how the density of ice compares to it.
Water has a density of approximately 1 gram per cubic centimeter (g/cm³) at standard conditions (1 atm pressure and 25°C temperature).
When water freezes and forms ice, its density changes. Ice has a slightly lower density than liquid water, which is why ice floats on water. The density of ice is about 0.92 g/cm³.
Now, assuming you know the amount of water that freezes in grams (let's call it "x" grams), you can calculate the resulting weight of the ice by using the ratio of their densities.
Weight of ice = (x grams) * (Density of ice / Density of water)
Weight of ice = x * (0.92 g/cm³ / 1 g/cm³)
Weight of ice = x * 0.92 grams
Therefore, the resulting weight of the ice would be x multiplied by 0.92 grams, where x is the amount of water that froze.