a 6.85ohm light bulb is connected to a 12.0v battery. how much current flows through the bulb. how much power bulb consume
To find the current flowing through the bulb, you can use Ohm's Law, which states that the current (I) flowing through a circuit is equal to the voltage (V) divided by the resistance (R). The formula is:
I = V / R
Given that the resistance of the bulb is 6.85 ohms and the voltage of the battery is 12.0V, you can plug these values into the formula:
I = 12.0V / 6.85 ohms
Calculating this:
I ≈ 1.75 Amperes (A)
Therefore, approximately 1.75 Amperes of current flows through the bulb.
To find the power consumed by the bulb, you can use the power formula which states that power (P) is equal to the product of the voltage (V) and the current (I). The formula is:
P = V * I
Using the given values:
P = 12.0V * 1.75A
Calculating this:
P ≈ 21 Watts (W)
Therefore, the bulb consumes approximately 21 Watts of power.