A 4.50-kg wheel that is 34.5 cm in diameter rotates through an angle of 13.8 rad as it slows down
uniformly from 22.0 rad/s to 13.5 rad/s. What is the magnitude of the angular acceleration of
the wheel?
A) 0.616 rad/s
B) 22.5 rad/s
C) 5.45 rad/s
D) 10.9 rad/s
E) 111 rad/s

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  1. W2^2 = W1^2 + 2*alpha*theta
    13.5^2 = 22.0^2 +2*alpha*13.8
    alpha = (13.5^2 - 22.0^2)/2*13.8
    = - 10.9 rad/s^2
    So, magnitude of angular acceleration = 10.9 rad/s^2

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