physics

A 4.50-kg wheel that is 34.5 cm in diameter rotates through an angle of 13.8 rad as it slows down
uniformly from 22.0 rad/s to 13.5 rad/s. What is the magnitude of the angular acceleration of
the wheel?
2
2
2
2
2

1. 👍 1
2. 👎 1
3. 👁 4,736
1. W2^2 = W1^2 + 2*alpha*theta
13.5^2 = 22.0^2 +2*alpha*13.8
alpha = (13.5^2 - 22.0^2)/2*13.8
So, magnitude of angular acceleration = 10.9 rad/s^2

1. 👍 2
2. 👎 1

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