which is the pah followed by a javelin projected horizontally by an athlete?

To calculate the horizontal range (pah) of a javelin projected horizontally by an athlete, you need to know the initial velocity of the javelin and the acceleration due to gravity.

Here's how you can find the pah using the following steps:

1. Determine the initial velocity (v) of the javelin. Assuming the athlete throws the javelin horizontally, the initial velocity in the horizontal direction will be equal to the athlete's throwing speed.

2. Find the time (t) it takes for the javelin to hit the ground. Since the javelin is projected horizontally, the vertical motion follows a standard free-fall trajectory. The time can be found using the formula t = sqrt((2h) / g), where h is the initial height (assuming it is zero) and g is the acceleration due to gravity (approximately 9.8 m/s^2).

3. Calculate the pah using the formula pah = v * t. Since the javelin is projected horizontally, the pah will be equal to the horizontal velocity multiplied by the time.

It's important to note that this calculation assumes ideal conditions and neglects air resistance, as well as any other external forces that might affect the motion of the javelin.

It is half of an inverted parabola. The javelin would immediately start to fall. The athlete will not win any competitions that way.