I can not get he correct answer -10.
-3/3{a+c(b+5)-(-6+a)}
a=1, b=-6, c=-4
starting with
-3/3{a+c(b+5)-(-6+a)}
= -3/3{1+(-4)((-6)+5)-(-6+1)}
let's work our way from the inside out:
-3/3{1+(-4)(-6+5)-(-6+1)}
-3/3{1+(-4)(-1)-(-5)}
-3/3{1+4+5)}
-3/3{10}
-1(10)
-10
Note that the division is done first, then the multiplication, left-to-right
To evaluate the expression, let's substitute the given values for a, b, and c and work step-by-step:
Given:
a = 1
b = -6
c = -4
-3/3{a+c(b+5)-(-6+a)}
Substitute the given values:
-3/3{(1 + (-4)(-6 + 5))-(-6+1)}
Simplify inside the parentheses:
-3/3{(1 + (-4)(-1))-(-5)}
Simplify the multiplication:
-3/3{(1 + 4)-(-5)}
Simplify inside the parentheses:
-3/3{(1 + 4) - (-5)}
Simplify further:
-3/3{5 + 5}
Add the numbers inside the parentheses:
-3/3{10}
Simplify further:
-3/3 * 10
Divide the numbers:
-1 * 10
The result is:
-10
To evaluate the expression, let's start by substituting the given values of a, b, and c into the expression:
-3/3{1 + (-4)(-6 + 5) - (-6 + 1)}
Now, simplify the terms inside the parentheses:
-3/3{1 + (-4)(-1) - (-5)}
Multiply the values inside the parentheses:
-3/3{1 + 4 + 5}
Combine the terms inside the curly braces:
-3/3{10}
Divide -3 by 3:
-1{10}
Multiplication takes precedence, so multiply -1 by 10:
-10
Therefore, the answer is -10.