1. A bag contains 3 red marbles, 2 blue marbles, and 5 green marbles. What is the probability of randomly selecting a red marble then, without replacing it, randomly selecting a green marble?
2. A bag contains 5 blue marbles, 6 red marbles, and 9 green marbles. Two marbles are drawn at random, one at a time and without replacement. What is the probability of selecting two red marbles?
3. 10 cards are numbered from 1 to 10 and placed in a box. One card is selected at random and is not replaced. Another card is then randomly selected. What is the probability of selecting two numbers that are less than 6?
4. DeAnna has 4 quarters, 3 dimes, and 3 nickels in her purse. She reaches into her purse and randomly grabs two coins, one at a time. What is the probability DeAnna will first grab a quarter and then, without replacing it, grab a nickel?
5. Two friends are taking an English class that has a monthly reading list. Once a student chooses a book from the list, no other student can choose that book. If there are 3 mystery and 4 romance books left, what is the probability that both friends randomly select a romance book, one after the other?
6. Two friends are taking an English class that has a monthly reading list. Once a student chooses a book from the list, no other student can choose that book. If there are 3 mystery and 4 romance books left, what is the probability that both friends randomly select a romance book, one after the other?
7. A sock drawer has 8 blue socks and 6 black socks. A sock is chosen at random. Then, without replacing that sock, another sock is chosen at random. What is the probability of choosing two blue socks?
what's the probability that someone wants to do your whole homework assignment? Do you have a specific question about one of these problems?
1. To find the probability of randomly selecting a red marble, and then without replacing it, randomly selecting a green marble, we need to consider both events separately.
First, let's find the probability of selecting a red marble. There are a total of 3 red marbles out of 10 marbles in the bag. So the probability of randomly selecting a red marble on the first draw is 3/10.
Next, we need to find the probability of selecting a green marble. After the first draw, there are 9 marbles left in the bag, with 5 of them being green. So the probability of randomly selecting a green marble on the second draw, without replacing the first marble, is 5/9.
To find the overall probability, we multiply the probabilities of each event since they are independent. Therefore, the probability of randomly selecting a red marble, and then without replacing it, randomly selecting a green marble is (3/10) * (5/9) = 15/90 = 1/6.
2. To find the probability of selecting two red marbles without replacement, we need to calculate the probability of the first draw being a red marble and the second draw being another red marble.
In the bag, there are a total of 20 marbles (5 blue + 6 red + 9 green). For the first draw, there are 6 red marbles out of the 20. Therefore, the probability of selecting a red marble on the first draw is 6/20.
After the first draw, there are 19 marbles left in the bag, with 5 of them being red. So the probability of selecting another red marble on the second draw, without replacing the first marble, is 5/19.
To find the overall probability, we multiply the probabilities of each event since they are independent. Therefore, the probability of selecting two red marbles without replacement is (6/20) * (5/19) = 30/380 = 3/38.
3. To find the probability of selecting two numbers less than 6, we need to calculate the probability of the first card being a number less than 6, and then without replacing it, the second card also being a number less than 6.
Out of the 10 cards, there are 5 numbers less than 6 (1, 2, 3, 4, and 5). So the probability of selecting a number less than 6 on the first draw is 5/10.
After the first draw, there are 9 cards left, with 4 of them being numbers less than 6. So the probability of selecting another number less than 6 on the second draw, without replacing the first card, is 4/9.
To find the overall probability, we multiply the probabilities of each event since they are independent. Therefore, the probability of selecting two numbers that are less than 6 is (5/10) * (4/9) = 20/90 = 2/9.
4. To find the probability of DeAnna first grabbing a quarter and then, without replacing it, grabbing a nickel, we need to consider both events separately.
First, let's find the probability of DeAnna grabbing a quarter. There are a total of 10 coins in her purse (4 quarters + 3 dimes + 3 nickels). So the probability of randomly grabbing a quarter on the first draw is 4/10.
After the first draw, there are 9 coins left in her purse, with 3 of them being nickels. So the probability of randomly grabbing a nickel on the second draw, without replacing the first coin, is 3/9.
To find the overall probability, we multiply the probabilities of each event since they are independent. Therefore, the probability of DeAnna first grabbing a quarter and then, without replacing it, grabbing a nickel is (4/10) * (3/9) = 12/90 = 2/15.
5. To find the probability that both friends randomly select a romance book, one after the other, we need to consider the number of remaining romance and mystery books.
Out of the total books remaining, there are 4 romance books and 3 mystery books left. Therefore, on the first draw, the probability of the first friend selecting a romance book is 4/(4+3) = 4/7.
After the first draw, there are (4-1) 3 romance books left out of (7-1) 6 books remaining. So the probability of the second friend selecting a romance book on the second draw, without replacing the first book, is 3/6.
To find the overall probability, we multiply the probabilities of each event since they are independent. Therefore, the probability that both friends randomly select a romance book, one after the other, is (4/7) * (3/6) = 12/42 = 2/7.
6. Apologies for the repetition in question 5. Please refer to the answer provided for question 5.
7. To find the probability of choosing two blue socks, we need to consider each draw separately.
First, let's find the probability of choosing a blue sock on the first draw. There are a total of 14 socks in the drawer (8 blue + 6 black). So the probability of randomly choosing a blue sock on the first draw is 8/14.
After the first draw, there are 13 socks left in the drawer, with 7 of them being blue. So the probability of randomly choosing another blue sock on the second draw, without replacing the first sock, is 7/13.
To find the overall probability, we multiply the probabilities of each event since they are independent. Therefore, the probability of choosing two blue socks is (8/14) * (7/13) = 56/182 = 28/91.
Steve is a d-bag lol.
Reporter: How will you fix the education system?
Donald Trump :Algebra is hard. I know algebra is hard. I took algebra. It's hard alright. Now we're going to fix that. Make America great again.