Use the method of substitution to solve the linear equation!
6a=6-b
6a=5-b
please help I don't get it it needs to be an ordered pair.
Look at the two equations. If 6a=6-b, substitute that into the other equation:
(6-b) = 5-b
add b to both sides and you have
6=5
There are no solutions to that "equation".
To solve the linear equation using the method of substitution, we need to solve one equation for one variable and substitute this expression into the other equation.
Let's start with the first equation: 6a = 6 - b.
Step 1: Solve for "a":
To get "a" alone on one side of the equation, we divide both sides by 6:
(6a)/6 = (6 - b)/6
a = 1 - (b/6)
Now, we have an expression for "a" in terms of "b."
Step 2: Substitute the expression for "a" into the second equation:
6a = 5 - b
Replace "a" with its value from step 1:
6(1 - (b/6)) = 5 - b
Step 3: Solve for "b":
Expand the equation:
6 - b = 5 - b
The "b" term cancels out, leaving us with:
6 = 5
However, this equation is not possible since 6 cannot equal 5. Therefore, there is no solution to this system of equations.
Hence, there is no ordered pair that satisfies both equations in this case.