Help please!i'm not sure if i'm right. Honestly i'm not that confident about most of my work.
In which of the following thermochemical equations would the deltaH be considered a heat of solution?
C6H6 (s)--> C6H6 (l), deltaH = +9.87 kJ
2C8H18(l) + 25O2 (g)-->16CO2 (g) + 18H2O (l), deltaH = 5,471 kJ/mol
2NaHCO3 (s)---> Na2CO3 (s) + H2O (g) + CO2 (g), deltaH = 129 kJ
NH4NO3 (s)--> NH4+ (aq) + NO3 (aq), deltaH = +25.7 kJ/mol<--- my answer
is it correct?
Yes, you are correct.
The first one is heat fusion.
The second is heat of combustion.
The third is heat of decomposition.
The fourth is heat of solution.
Yes, your answer is correct. In the thermochemical equation NH4NO3 (s) --> NH4+ (aq) + NO3 (aq), the deltaH value of +25.7 kJ/mol indicates that it is a heat of solution. This means that energy is absorbed or released during the process of dissolving NH4NO3 in water.
To determine which thermochemical equation represents a heat of solution, you need to understand what a heat of solution means. The heat of solution refers to the enthalpy change that occurs when a solute dissolves in a solvent.
In the given equations, we can identify the heat of solution by looking for a solid substance that dissolves in a liquid or aqueous solution, resulting in a change in enthalpy.
Let's analyze each equation:
1. C6H6 (s) -> C6H6 (l), deltaH = +9.87 kJ
This equation represents the phase change of benzene from solid to liquid. It does not involve the dissolution of a solute in a solvent, so it is not a heat of solution.
2. 2C8H18(l) + 25O2 (g) -> 16CO2 (g) + 18H2O (l), deltaH = 5,471 kJ/mol
This equation represents the combustion of octane (C8H18) to produce carbon dioxide and water. It does not involve the dissolution of a solute in a solvent, so it is not a heat of solution.
3. 2NaHCO3 (s) -> Na2CO3 (s) + H2O (g) + CO2 (g), deltaH = 129 kJ
In this equation, sodium bicarbonate (NaHCO3) dissolves in water, forming sodium carbonate (Na2CO3) and releasing carbon dioxide and water vapor. This is indeed a heat of solution because a solid is dissolving in a liquid solvent, resulting in a change in enthalpy. So, your answer is correct.
4. NH4NO3 (s) -> NH4+ (aq) + NO3- (aq), deltaH = +25.7 kJ/mol
This equation represents the dissociation of ammonium nitrate (NH4NO3) into its ions in an aqueous solution, which does not involve the dissolution of a solid solute in a liquid solvent. Therefore, it is not a heat of solution.
In conclusion, equation 3 (2NaHCO3 (s) -> Na2CO3 (s) + H2O (g) + CO2 (g), deltaH = 129 kJ) represents a heat of solution.
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