Sasha wants to find the resistance of the motor. She measured a 6 V drop across the motor that is in a series circuit with a 200 ohms reseistor. The power source is supplying 9 V to the circuit. How musch resistance is her motor putting into the circuit?

3 volts

To find the resistance of the motor, we can use Ohm's Law, which states that the resistance (R) is equal to the voltage drop (V) across the motor divided by the current (I) flowing through the circuit.

In this case, we know that there is a 6 V drop across the motor and the power source is supplying 9 V. Therefore, the voltage drop across the resistor must be 9 V - 6 V = 3 V.

Since the resistor and motor are in a series circuit, the current flowing through the circuit is the same. We can use Ohm's Law again to find the current (I) flowing through the circuit:

I = V / R, where V is the voltage drop across the resistor and R is the resistance of the resistor.

Given that the voltage drop across the resistor is 3 V and the resistance of the resistor is 200 ohms, we can find the current:

I = 3 V / 200 ohms

Simplifying, we get:

I = 0.015 A

Since the motor and resistor are connected in series, the current flowing through the motor is also 0.015 A.

Now, we can use Ohm's Law to find the resistance (R) of the motor:

R = V / I, where V is the voltage drop across the motor and I is the current flowing through the motor.

Given that the voltage drop across the motor is 6 V and the current flowing through the motor is 0.015 A, we can calculate the resistance:

R = 6 V / 0.015 A

Simplifying, we get:

R = 400 ohms

Therefore, the resistance of Sasha's motor is 400 ohms.

To find the resistance of the motor, we will use Ohm's law, which states that the voltage (V) across a component is equal to the current (I) passing through it, multiplied by the resistance (R) of the component. The formula is V = I * R.

In this case, Sasha measured a 6 V drop across the motor. We know that the power source is supplying 9 V to the circuit and the resistor has a resistance of 200 ohms.

First, we need to find the voltage across the motor. Since the voltage across the resistor (6 V) and the voltage across the power source (9 V) must add up to the total voltage in the circuit, we can subtract the voltage across the resistor from the total voltage to find the voltage across the motor.

Voltage across the motor = Total voltage - Voltage across the resistor
Voltage across the motor = 9 V - 6 V
Voltage across the motor = 3 V

Now, we can use Ohm's law to find the resistance of the motor.

Resistance of the motor = Voltage across the motor / Current passing through the motor

However, we don't have the current passing through the motor directly. We can calculate the current using Ohm's law applied to the resistor.

Current passing through the resistor = Voltage across the resistor / Resistance of the resistor
Current passing through the resistor = 6 V / 200 Ω
Current passing through the resistor = 0.03 A

Since the motor and the resistor are in series, the same current passes through both.

Current passing through the motor = Current passing through the resistor
Current passing through the motor = 0.03 A

Now, we can substitute the values into the formula to find the resistance of the motor.

Resistance of the motor = Voltage across the motor / Current passing through the motor
Resistance of the motor = 3 V / 0.03 A
Resistance of the motor = 100 Ω

Therefore, the motor is putting 100 ohms of resistance into the circuit.