A lead ball has a volume of 94.3 cm3 at 19.3°C. What is the change in volume when its temperature changes to 34.3°C?
94.4cm3 was the answer I put and I was wrong. Can someone help?
To solve this question, you can use the coefficient of volume expansion formula:
ΔV = V₀ * β * ΔT
Where:
ΔV is the change in volume
V₀ is the initial volume
β is the coefficient of volume expansion
ΔT is the change in temperature
In order to use this formula, you need to know the coefficient of volume expansion for lead, which is given as 0.000029 (1/°C).
Let's calculate the change in volume:
V₀ = 94.3 cm³ (given initial volume)
ΔT = 34.3°C - 19.3°C = 15°C (change in temperature)
β = 0.000029 (given coefficient of volume expansion)
Plugging in these values into the formula:
ΔV = 94.3 cm³ * 0.000029 (1/°C) * 15°C
Now, let's solve this equation:
ΔV = 0.040817 cm³
Therefore, the change in volume when the temperature changes from 19.3°C to 34.3°C is approximately 0.040817 cm³.
Please note that the correct answer may vary based on the rounding of intermediate values during calculations. Make sure to check whether your final answer is rounded correctly to the appropriate number of significant figures.