A lead ball has a volume of 94.3 cm3 at 19.3°C. What is the change in volume when its temperature changes to 34.3°C?
Someone on here has already answered this but it was wrong!
To solve this problem, we can use the equation for thermal expansion:
ΔV = V₀ * β * ΔT
Where:
ΔV is the change in volume,
V₀ is the initial volume,
β is the coefficient of volume expansion for the material (lead in this case), and
ΔT is the change in temperature.
First, we need to calculate the initial volume. Given that the volume is 94.3 cm³ at 19.3°C, the initial volume is 94.3 cm³.
Next, we need the coefficient of volume expansion for lead. The coefficient of volume expansion for lead is typically given as 0.0000291 per °C.
Finally, we can find the change in volume when the temperature changes to 34.3°C.
ΔT = 34.3°C - 19.3°C = 15°C
Now, we can plug the values into the formula:
ΔV = 94.3 cm³ * 0.0000291 per °C * 15°C = 0.0406 cm³
Therefore, the change in volume when the temperature changes to 34.3°C is approximately 0.0406 cm³.