You (65 kg) are standing in an elevator traveling upward that passes the 3rd floor at 3.5 m/s and then passes the 4th floor at 4.5 m/s one second later. Find the normal force exerted on your feet by the elevator while it is passing between these floors.

I got 6565 N, because acceleration is 1, Fnet = ma which is 65, and WE1 is -6500 N, but that isn't the right answer.

Thanks so much for any help you can give me!

The floor must accelerate the person as well as support his or her weight. Acceleration is upward at 1.0 m/s^2

I don't understand what your "WE1" is or how you came up with it.

F(on feet) = M*(g + a)
= 65*(9.8 + 1.0) = 702 N

To find the normal force exerted on your feet by the elevator, we need to consider the forces acting on you while the elevator is passing between the 3rd and 4th floors.

First, let's determine the acceleration of the elevator during this time period. We know that it passes the 3rd floor at 3.5 m/s and the 4th floor at 4.5 m/s one second later. The change in velocity (Δv) is 4.5 m/s - 3.5 m/s = 1 m/s. The time interval (Δt) is 1 second. Therefore, the acceleration (a) can be calculated using the formula a = Δv/Δt:

a = 1 m/s / 1 s = 1 m/s²

Now, let's consider the forces acting on you. Since you are in an elevator traveling upward, your weight (W) is acting downward and the normal force (N) exerted by the elevator on your feet is acting upward.

Using Newton's second law, we can write the equation of motion in the vertical direction:

ΣF = ma

Where ΣF is the net force, m is your mass (65 kg), and a is the acceleration (1 m/s²). Now let's calculate the net force:

ΣF = ma
N - W = ma

Substituting the values:

N - 65 kg × 9.8 m/s² = (65 kg) × (1 m/s²)

N - 637 N = 65 N

N = 65 N + 637 N

N = 702 N

Therefore, the normal force exerted on your feet by the elevator while it is passing between the 3rd and 4th floors is 702 N.

To find the normal force exerted on your feet by the elevator, we need to consider the forces acting on you in this scenario.

1. First, let's calculate the acceleration of the elevator. The change in velocity between the 3rd and 4th floor is (4.5 m/s - 3.5 m/s) = 1 m/s.

2. The time taken for this change in velocity is 1 second. So, the acceleration can be calculated as a = Δv / t = 1 m/s / 1 s = 1 m/s².

3. The net force acting on you in the elevator is given by the equation F_net = m * a, where m is your mass (65 kg).

F_net = (65 kg) * (1 m/s²) = 65 N

4. Now, let's consider the forces acting on you. The force of gravity acting on you is given by F_gravity = m * g, where g is the acceleration due to gravity (approximately 9.8 m/s²).

F_gravity = (65 kg) * (9.8 m/s²) = 637 N

5. The normal force exerted on your feet by the elevator is equal in magnitude and opposite in direction to the force of gravity. Therefore, the normal force is also 637 N.

Please note that your calculation of 6565 N is not correct. Make sure you double-check your calculation steps.