A paperweight, when weighed in air, has a weight of W = 6.95 N. When completely immersed in water, however, it has a weight of Win water = 4.26 N. Find the volume of the paperweight.

Would I multiply the two values of weight and then by the density of water?

4.26=weightinair-forcebouyancy

4.26=6.95-desnisitywater*g*volume

solve for volume

Full solutions of these question

Well, if you multiply the two values of weight and then by the density of water, you'll end up with the mass of the paperweight, not the volume. But fear not, my friend. There's a magical thing called Archimedes' principle that can come to our rescue here.

Archimedes' principle states that the buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid that the object displaces. So, we can use this principle to find the volume of the paperweight.

Since the weight when completely immersed in water is 4.26 N, that means the buoyant force acting on the paperweight is 4.26 N. And since the weight in air is 6.95 N, the weight of the paperweight itself is 6.95 N.

Now, according to Archimedes' principle, the weight of the fluid displaced is equal to the buoyant force. Therefore, the weight of the fluid displaced is also 4.26 N.

Do you see where we're going with this? The weight of the fluid displaced is equal to the weight of the paperweight minus the weight in air. So, 4.26 N = 6.95 N - X (where X is the weight in air).

Solving for X, we get X = 6.95 N - 4.26 N = 2.69 N.

Now we know that the weight of the fluid displaced is 2.69 N. And since we know that the weight of the fluid displaced is equal to its mass times the acceleration due to gravity, we can use the density of water to find the volume.

The formula for density is mass divided by volume. Rearranging the formula, we get mass = density times volume. So, in this case, mass = density of water times volume of the paperweight.

We now have all the pieces of the puzzle to solve for the volume. Plug in the values we know: 2.69 N (weight of fluid displaced) = density of water times volume.

Rearranging the formula, we get volume = 2.69 N / (density of water).

So, to find the volume of the paperweight, divide 2.69 N by the density of water. And voila! You've got your volume! Just be careful not to drop it on your foot when handling the paperweight. Safety first, you know?

To find the volume of the paperweight, you can use the concept of buoyancy. Here's how you can approach the problem:

1. Start by finding the weight of the paperweight in water. The weight of the paperweight in water (Win water) is given as 4.26 N.

2. Apply Archimedes' principle, which states that the buoyant force acting on an object immersed in a fluid is equal to the weight of the fluid displaced by the object. In this case, the buoyant force is equal to the weight of water that the paperweight displaces.

3. Calculate the weight of water displaced by the paperweight. The weight of water displaced is equal to the weight of the paperweight in air (W) minus the weight of the paperweight in water (Win water).

Weight of water displaced = W - Win water

Substituting the given values, we have:
Weight of water displaced = 6.95 N - 4.26 N = 2.69 N

4. Use the density of water to find the volume of water displaced. The density of water is approximately 1000 kg/m³. The weight of water displaced can be related to the volume of water displaced using the formula:

Weight = Density x Volume x Acceleration due to gravity

Rearranging the formula, we get:
Volume = Weight / (Density x Acceleration due to gravity)

Substituting the values, we have:
Volume = 2.69 N / (1000 kg/m³ x 9.8 m/s²)

Volume = 0.000275 m³ (approximately)

Therefore, the volume of the paperweight is approximately 0.000275 cubic meters.

(4.26-6.96)/(1000*9.8)=volume