A train travels at a speed of 24 m/s. Then it slows down uniformly at 0.065 m/s2 until it stops. What distance does the train travel while slowing down?

convert 4430.75m into km and you get 4.43075km.round it off and its 4.4km.theres the distance mimi

mantap

it takes 24/.065 = 369.23 sec to decelerate to zero.

In that time it travels s = 1/2 at^2 = 1/2 (.065)(369.23^2) = 4430.75 m

whats the distance

To find the distance the train travels while slowing down, we need to use the equation of motion that relates the initial velocity (u), final velocity (v), acceleration (a), and distance (s).

The initial velocity of the train is given as 24 m/s (u = 24 m/s).
The acceleration is given as -0.065 m/s^2 since the train is slowing down (a = -0.065 m/s^2).
The final velocity when the train comes to a stop is 0 m/s (v = 0 m/s).

The equation we can use is:
v^2 = u^2 + 2as

Since we want to find the distance traveled while slowing down, s is what we need to solve for.

Rearranging the equation, we get:
s = (v^2 - u^2) / (2a)

Substituting the given values, we have:
s = (0^2 - 24^2) / (2 * -0.065)

Now we can calculate the distance traveled while slowing down:
s = (0 - 576) / (-0.13)
s = 576 / 0.13
s ≈ 4430.77 meters

Therefore, the train travels approximately 4430.77 meters while slowing down.