What volume of a 2.5 M stock solution of acetic acid (HC2H3O2) is required to prepare 100.0 milliliters of a 0.50 M acetic acid solution?

0.020 liters is the correct answer

You don't need to do a balanced equation for this one. 2.5x =.100(.50)

x=.020 this would be 20 ml
the formula is Liters x Molarity =Moles
so 2.5Molar times x # of liters =.100 x.50
answer is 20ml

20ml

How would you put it into a equation

To find the required volume of the 2.5 M stock solution, we can use the equation:

M1V1 = M2V2

Where:
M1 = Initial concentration of the stock solution = 2.5 M
V1 = Volume of the stock solution to be calculated
M2 = Final concentration of the desired solution = 0.50 M
V2 = Volume of the desired solution = 100.0 mL

Rearranging the equation to solve for V1:

V1 = (M2 * V2) / M1

Let's substitute the given values into the equation and calculate the volume V1:

V1 = (0.50 M * 100.0 mL) / 2.5 M
= (0.50 * 100.0) / 2.5
= 50.0 / 2.5
= 20.0 mL

Therefore, 20.0 milliliters of the 2.5 M stock solution of acetic acid is required to prepare 100.0 milliliters of a 0.50 M acetic acid solution.