A 60 kg high jumper lands on a foam pit and comes to rest. If the pit is able to exert an average force of 600 N on the high jumper in breaking the fall, what is the jumper’s acceleration?

Do you remember the formula F = ma? I hope so.

a = F/m = 10 m/s^2

To find the jumper's acceleration, we can use Newton's second law of motion, which states that the force acting on an object is equal to its mass multiplied by its acceleration (F = m * a).

Given:
Mass of the high jumper (m) = 60 kg
Force exerted by the foam pit (F) = 600 N

We can rearrange the formula to solve for acceleration (a):
a = F / m

Now we can substitute the values into the formula:
a = 600 N / 60 kg

Calculating this, acceleration (a) is equal to 10 m/s².

Therefore, the high jumper's acceleration is 10 m/s².