Determine the work done by the force F = [1, 4], in newtons, for an object moving along the vector d = [6, 3], in meters.
F dot d = |F| |d| cos theta = 6+12 = 18 Joules
thankyou!
To determine the work done by a force, we can use the formula:
Work = Force dot Product Distance
Where "Force" is the vector representing the force applied in newtons, "Distance" is the vector representing the displacement of the object in meters, and the dot product represents the dot product operation between the two vectors.
Given that the Force vector F = [1, 4], and the displacement vector d = [6, 3], we can calculate the dot product by multiplying the corresponding components of the vectors and summing them:
F dot d = (1*6) + (4*3) = 6 + 12 = 18
Therefore, the work done by the force F on the object is 18 newton-meters (N⋅m) or joules (J).