what is the weight of a 3.0 kg object on the surface of the earth?

W=mg =3•9.8 = 29.4 N

someone told me answer was 29, but how did they get answer? and is it correct?

Weight=mass x acceleration due to gravity

W=mg
W=(3.0kg)(9.81m/s^2)
W=29.43 N

thank you

To calculate the weight of an object on the surface of the Earth, you need to multiply its mass by the acceleration due to gravity. The acceleration due to gravity on Earth is approximately 9.8 m/s^2.

So, to find the weight of a 3.0 kg object on the surface of the Earth, you multiply its mass (3.0 kg) by the acceleration due to gravity (9.8 m/s^2):

Weight = Mass x Acceleration due to gravity

Weight = 3.0 kg x 9.8 m/s^2

Weight = 29.4 N

Therefore, the weight of a 3.0 kg object on the surface of the Earth is approximately 29.4 Newtons (N).